Simultaneous eqns: 1/4(9+x)+10=-3+1/2x and x/(x-4) + 2/(x+3)=1

[Rachellowes]

I am having real trouble trying to solve these two pairs of equations... any help you could give me would be greatly appreciated.

1) 1/4(9+x)+10=-3+1/2x




2) x 2
-------- + --------- = 1
x-4 x+3


TIA.

 

[Otis]

Simultaneous equations.

I am having real trouble trying to solve these two pairs of equations...

1) 1/4(9+x)+10=-3+1/2x

2) x 2
-------- + --------- = 1
x-4 x+3

Hi. I see two equations, not two pairs of equations.

If these come from two different exercises, then you do not have simultaneous equations. Solve each one separately.

Please post what you already tried for each attempt.

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Note: We cannot "draw" algebraic fractions on this web site because extra spaces are removed by the system (unless you use the CODE tags).

Instead, you can type the second equation like this:

x/(x-4) + 2/(x+3) = 1

 

[Rachellowes]

Hi. I see two equations, not two pairs of equations.

If these come from two different exercises, then you do not have simultaneous equations. Solve each one separately.

Please post what you already tried for each attempt.

---

Note: We cannot "draw" algebraic fractions on this web site because extra spaces are removed by the system (unless you use the CODE tags).

Instead, you can type the second equation like this:

x/(x-4) + 2/(x+3) = 1

Thank you for the advice!

 

[Rachellowes]

thanks,

So far for 1) 49/4 + x/4 = -3 + 1/2x

49/4-x/4 = -3 + x/2

stuck from here...

for 2)

I am really struggling....

 

[stapel]

1) 1/4(9+x)+10=-3+1/2x

As posted, this equation may mean the following:

. . . . .\(\displaystyle \dfrac{1}{4\, (9\, +\, x)}\, +\, 10\, =\, -\, 3\, +\, \dfrac{1}{2x}\)

Is this correct?

2) x 2
-------- + --------- = 1
x-4 x+3

To learn how to type math as text, please review this article. I think you meant to type something along the lines of this:

. . . . .x/(x - 4) + 2/(x + 3) = 1

...which typesets as:

. . . . .\(\displaystyle \dfrac{x}{x\, -\, 4}\, +\, \dfrac{2}{x\, +\, 3}\, =\, 1\)

Is this correct?

So far for 1) 49/4 + x/4 = -3 + 1/2x

How did you get this? What were your steps?

Note: Your subject line refers to solving "simultaneous" equations, which means that you have been given two equations in two unknowns (usually "x" and "y"), or three equations in three unknowns, etc, which are to be solved together, or simultaneously. You were asked if that was actually what you meant here, but your only response was "thanks". We still need to know if these two equations are really meant to be solved together (in which case, we need corrected versions containing the second variable) or not (in which case, please correct the instructions from "solving simultaneous equations" to "solving rational equations").

By the way, to learn how to solve rational equations, in case that's what you're really asking after, try here.