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Simplish algebra problem has me stuck
- Thread starter lowend
- Start date
You have the correct LCD, but leaving it as 4(x+2) would allow you to see the cancellations better, I believe.
\(\displaystyle 3\cdot 4(x+2)-4(\not{x}\not{+}\not{2})\cdot\frac{2x-1}{\not{x}\not{+}\not{2}}=\frac{1}{\not{4}}\cdot \not{4}(x+2)\)
\(\displaystyle 12x+24-4(2x-1)=x+2\)
\(\displaystyle 12x+24-8x+4=x+2\)
Continue.
\(\displaystyle 3\cdot 4(x+2)-4(\not{x}\not{+}\not{2})\cdot\frac{2x-1}{\not{x}\not{+}\not{2}}=\frac{1}{\not{4}}\cdot \not{4}(x+2)\)
\(\displaystyle 12x+24-4(2x-1)=x+2\)
\(\displaystyle 12x+24-8x+4=x+2\)
Continue.
Just another way (my preference with these):lowend said:1/4 = 3 - [(2x-1)/(x+2)]
Re-arrange:
(2x-1) / (x+2) = 3 - 1/4
(2x-1) / (x+2) = 11 / 4
4(2x-1) = 11(x + 2)
Keep on...