M Moonseed New member Joined Jun 15, 2006 Messages 1 Jun 15, 2006 #1 I got stumped by this question: log a 2x + 3(log a x - log a y) I tried making the logs in the parentheses log a x / log a y but I don't know what to do after that.
I got stumped by this question: log a 2x + 3(log a x - log a y) I tried making the logs in the parentheses log a x / log a y but I don't know what to do after that.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jun 15, 2006 #2 \(\displaystyle \ \log _a (2x) + 3\left( {\log _a (x) - \log _a (y)} \right) = \log _a (2x) + 3\left( {\log _a \left( {\frac{x}{y}} \right)} \right) = \log _a (2x) + \left( {\log _a \left( {\frac{{x^3 }}{{y^3 }}} \right)} \right) = \left( {\log _a \left( {\frac{{2x^4 }}{{y^3 }}} \right)} \right)\)
\(\displaystyle \ \log _a (2x) + 3\left( {\log _a (x) - \log _a (y)} \right) = \log _a (2x) + 3\left( {\log _a \left( {\frac{x}{y}} \right)} \right) = \log _a (2x) + \left( {\log _a \left( {\frac{{x^3 }}{{y^3 }}} \right)} \right) = \left( {\log _a \left( {\frac{{2x^4 }}{{y^3 }}} \right)} \right)\)