simplifying help
- Thread starter jbreu
- Start date
- Joined
- Apr 12, 2005
- Messages
- 11,339
Kind of a smoke screen on this one.
12*(7/6) = 14 -- That part's pretty obvious.
3*(7/6) = 7/2
It is not immedately clear how to get to your form until one observes cos(7pi/2) = 0
The, if we REALLY want to, we can do this cos(14pi) - cos(7pi/2) = cos(14pi) - 0 = cos(14pi) = cos(14pi - 0)
I can't think of a single reason ayone would want to do that, but there it is.
12*(7/6) = 14 -- That part's pretty obvious.
3*(7/6) = 7/2
It is not immedately clear how to get to your form until one observes cos(7pi/2) = 0
The, if we REALLY want to, we can do this cos(14pi) - cos(7pi/2) = cos(14pi) - 0 = cos(14pi) = cos(14pi - 0)
I can't think of a single reason ayone would want to do that, but there it is.
D
Deleted member 4993
Guest
jbreu said:
Was your problem as posted? Let me re-write it:
cos[12(7pi/6) - cos{3(7pi/6)}]
Although it is a valid expression - I cannot for life of me think of a situation where you would get this expression (in a physically significant problem).
More likely expression would be:
cos {12(7pi/6)} - cos{3(7pi/6))} =