Simplifying expressions containing rational exponents by fac

[lmkeefe70]

3/5(x+1)^5/3+3/4(x+1)^8/3

 

[royhaas]

Your expression may be ambiguous but perhaps $\displaystyle 3(x+1)^{5/3}$ is a common factor.

 

[Denis]

3/5(x+1)^5/3

Can you bit a bit clearer :shock:

Is that (3/5) times (x + 1)^5 divided by 3 ?

If so, this makes it clear: [(3/5)(x + 1)^5] / 3

 

[lmkeefe70]

3/5(x+1)^5/3

Can you bit a bit clearer :shock:

Is that (3/5) times (x + 1)^5 divided by 3 ?

If so, this makes it clear: [(3/5)(x + 1)^5] / 3

Sorry the problem is:3/5(x+1)^5/3 + 3/4(x+1)^8/3

 

[Denis]

What you smoking keefe?