simplifying an equation

Joanie10

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Aug 1, 2010
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I would like to know if I am on the right track in simplyfing this problem: ?x^3y^3 + xy?xy = x^3/2y^3/2. Thanks.
 
Tough to tell. You'll have to improve the notation. Add parentheses for clarity.
 
Joanie10 said:
I would like to know if I am on the right track in simplyfing this problem:

Joanie10,

did you intend this, *using the parentheses* as grouping symbols?


?(x^3y^3) + xy?(xy) = ?


\(\displaystyle \sqrt{x^3y^3} \ + \ xy\sqrt{xy} \ = \ ?\)
 
The bold equation shown by you is the original problem I need to work and simplify.

I think maybe it can be worked by quadractic where I can use distribution. I have no examples to go by. I am an online student so basically I am being self-taught and have a hard time rewriting problems.
 
Thank you, now I see I was trying to take it not only in the wrong direction at first but step too far also. This direction makes a lot more sense. Thanks a bunch.
 
This is what I came up with.

?x^3 y^3 + xy?xy
?(x^3 y^3 ) + ?(x+y)(x+y)
?(x^3 y^3 ) = ?(x^2 + xy +yx + y^2)
?(x^3 y^3) = ?(x^2 y^2 +2y) = x^3+2 y^3+2 +2y = x^5 y^5 +2y
 
Joanie10 said:
This is what I came up with.

?x^3 y^3 + xy?xy
?(x^3 y^3 ) + ?(x+y)(x+y)
?(x^3 y^3 ) = ?(x^2 + xy +yx + y^2)
?(x^3 y^3) = ?(x^2 y^2 +2y) = x^3+2 y^3+2 +2y = x^5 y^5 +2y
No. Sorry, but you really need help from a face-to-face tutor.
Here's the solution anyway:
SQRT(x^3 y^3) + xySQRT(xy)

= SQRT(x^2 y^2 x y) + xySQRT(xy)

= xySQRT(xy) + xySQRT(xy)

= 2xySQRT(xy) ; that's it.
 
I had to turn in my paper. Of course, I missed the question since I could not answer it in time. The correct answer is below courtesy of my professor.

?x^3y^3 + xy?xy

xy?xy + xy?xy

2xy?xy
 
Joanie10 said:
I had to turn in my paper. Of course, I missed the question since I could not answer it in time. The correct answer is below courtesy of my professor.
?x^3y^3 + xy?xy
xy?xy + xy?xy
2xy?xy
That's the same as I gave you in my last post....can you "see" that?
I suggest you make sure you understand WHY that's the answer; else you haven't gained anything.
 
Joanie10 said:
I would like to know if I am on the right track in simplyfing this problem: ?x^3y^3 + xy?xy = x^3/2y^3/2. Thanks.

Joanie, as it turns out, I *dId* have the correct interpretation from you.

And you are not simplifying an equation; you are simplifying an expression.
 
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