simplifying (5+3 to 2nd power) divided by 7 times 6 to 2nd p

[chirs11188]

i need help on how you would simplify

(5+3 to the second power) divided by 7 times 6 to the second power

thank you

 

[Deleted member 4993]

i need help on how you would simplify

(5+3 to the second power) divided by 7 times 6 to the second power

thank you

Does your problem look as follows:

\(\displaystyle \frac{5 \, + \, 3^2}{7 \, \cdot \, 6^2}\)

if yes then you should post it as

(5 + 3^2)/(7 * 6^2)

To start use hierchy of operations (PEMDAS)

Duplicate post:

viewtopic.php?f=13&t=32326&p=125404#p125404

Please show us your work indicating exactly where you are stuck - so that we where to begin to help you.

 

[isimmons]

Parenthesis and exponents first. When I started beginning algebra I had never heard of (PEMDAS). It was never covered in my basic math classes.

Take care of the exponents first.
Rewrite as (5 + 9)/(7 * 36)

If it's in the form of a fraction treat the top part (numerator) as a separate problem from the bottom part (denominator) until they are both simplified as much as possible. Do 5+9=14 and then do 7 * 36=252
Rewrite as 14/252

Now simplify the fraction. 2 goes into 14, 7 times and 2 goes into 252, 126 times.
Rewrite as 7/126

7 goes into 7, 1 time and 7 goes into 126, 18 times
Rewrite as 1/18

If the instructor or the book asks for a decimal,
The decimal answer would be 0.055555556 (1 divided by 18) but most of the time the reduced fraction is the answer your looking for.

 

[Deleted member 4993]

Parenthesis and exponents first. When I started beginning algebra I had never heard of (PEMDAS). It was never covered in my basic math classes.

Different system uses different acronyms - but ~50 years ago when I learned my pre-algebra in India - I learned it with an acronym.