square root 56 divided by square root 35
C cecil New member Joined Oct 30, 2011 Messages 4 Oct 30, 2011 #1 square root 56 divided by square root 35
N namestek007 New member Joined Nov 27, 2011 Messages 3 Dec 1, 2011 #2 \(\displaystyle $${{\sqrt{56}}\over{\sqrt{35}}}={{2\,\sqrt{14}}\over{\sqrt{35}}}={{2\,\sqrt{2}}\over{\sqrt{5}}}$$\)
\(\displaystyle $${{\sqrt{56}}\over{\sqrt{35}}}={{2\,\sqrt{14}}\over{\sqrt{35}}}={{2\,\sqrt{2}}\over{\sqrt{5}}}$$\)
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Dec 1, 2011 #3 namestek007 said: \(\displaystyle ={{2\,\sqrt{2}}\over{\sqrt{5}}}\) Click to expand... Is that your final answer? My answer: . \(\displaystyle \frac{2}{5} \sqrt{10}\) .
namestek007 said: \(\displaystyle ={{2\,\sqrt{2}}\over{\sqrt{5}}}\) Click to expand... Is that your final answer? My answer: . \(\displaystyle \frac{2}{5} \sqrt{10}\) .
N namestek007 New member Joined Nov 27, 2011 Messages 3 Dec 1, 2011 #4 mmm4444bot said: Is that your final answer? My answer: . \(\displaystyle \frac{2}{5} \sqrt{10}\) . Click to expand... Your answer is better
mmm4444bot said: Is that your final answer? My answer: . \(\displaystyle \frac{2}{5} \sqrt{10}\) . Click to expand... Your answer is better