simplify

[sportsaholic2397]

(x^2+5x+6/x+2) * (x+1/x^2+3x-3)

help me get off on the right foot. i am not sure how to start and hopefully with a lead it can help me figure it out!

 

[sportsaholic2397]

alright so i took a stab at it, but not sure if it is right,

(x^2+5x+6/x+2) * (x+1/x^2+3x-3)=

(x+3) (x+2) * x+1
(x+2) .... (x+3) (x-1) (ignore the dots, not good at using this engine...)

this is where i am not sure if i am doing it correctly but from there do you eliminate via cross multiplication which would give me this,

x+1
x-1

 

[galactus]

Please try to use proper grouping symbols.

I assume you mean \(\displaystyle \frac{x^{2}+5x+6}{x+2}\cdot\frac{x+1}{x^{2}+3x-3}\)

What you have is \(\displaystyle (x^{2}+5x+\frac{6}{x}+2)(x+\frac{1}{x^{2}}+3x-3)\)

Are you sure that \(\displaystyle x^{2}+3x-3\) is correct?. That does not factor. It doesn't have to. Just thought it should. They do in most of these problems.

Maybe it should be \(\displaystyle x^{2}+2x-3\). If that was a typo, then that is a whole nuther matter.

If so, then you are correct.

 

[sportsaholic2397]

yeah you are right it is suppose to be x^2+2x-3.

x+1
x-1
so my answer ^ is correct?

 

[galactus]

Yep