simplify trig (sinx-kcosx)/(cosx+ksinx), k=constant

[dagr8est]

This is actually for a physics problem and there may not be a way to simplify it. I was just wondering if anyone saw a way to simplify it so my solution would look nicer. Any help is appreciated.

(sinx-kcosx)/(cosx+ksinx) where k is a constant

 

[mark07]

Looks simple enough to me.

 

[Count Iblis]

This is actually for a physics problem and there may not be a way to simplify it. I was just wondering if anyone saw a way to simplify it so my solution would look nicer. Any help is appreciated.

(sinx-kcosx)/(cosx+ksinx) where k is a constant

\(\displaystyle \frac{\sin(x)-k\cos(x)}{\cos(x)+k\sin(x)}=\tan(x-\theta)\)

where

\(\displaystyle \theta=\arctan(k)\)