simplify the following, leaving the answer in index form?

[jacob_1988]

Hello,
Please could someone help me with this particular question, have I managed to correctly answer the question below, if not, how I would go about this?

Question: simplify the following, leaving the answer in index form.
2⁴ x 2³ = is the answer 1.28 x 10²?

thank-you.

 

[pka]

Hello,
Please could someone help me with this particular question, have I managed to correctly answer the question below, if not, how I would go about this?
Question: simplify the following, leaving the answer in index form.
2⁴ x 2³ = is the answer 1.28 x 10²?

\(\displaystyle 2^4\cdot 2^3=2^{4+3}=2^7=128\) now \(\displaystyle 128=1.28\cdot 100=1.28\cdot10^2\).

 

[Bob Brown MSEE]

Index Form

Hello,
Please could someone help me with this particular question, have I managed to correctly answer the question below, if not, how I would go about this?

Question: simplify the following, leaving the answer in index form.
2⁴ x 2³ = is the answer 1.28 x 10²?

thank-you.

http://www.mathsteacher.com.au/year7/ch02_power/07_index/ind.htm
I was not familiar with the "index form" of a number.
It appears that "index form" means "factored form" with exponents used to indicate repeated prime factors.
If that is your definition then..
ANSWER: 2⁷​

 

[jacob_1988]

7[/SUP]​

Foremost: thank-you for the answer(s) above I fervently appreciate the help! I have been told (by my teacher) the answer is 2 to the power of 7 (2⁷), by adding the powers and leaving the answer in powers. Moreover; would 3⁷ x 3³ divided by 3⁴ = 3⁶? I.e. (3⁷ x 3³ divided by 34 = 729) (3⁶ = 729)?

 

[lookagain]

Moreover; would 3⁷ x 3³ divided by 3⁴ = 3⁶?\(\displaystyle \ \ \ \ \)Yes.

I.e. (3⁷ x 3³ divided by 3^4 = 729) (3⁶ = 729)?\(\displaystyle \ \ \ \ \)You were missing some character to indicate 3 raised to the 4th power.

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