Simplify sqrt[a^5 b^6], (sqrt[72] + sqrt[26])sqrt[13]

[Guest]

How do I simplify the sqrt of (a^5b^6)?

What I did before was take the square roots and multiply them to cancel out and square rooting....like sqrt of a times sqrt of a = a...

So then the answer I got to this problem was a^2 times b^3 times sqrt of A

Apparently that is incorrect, so what did I do wrong and how do I get the right answer?


Also, how do I

?

This is what I did:

1st Step: 6 times sqrt 2 + sqrt 13 t times sqrt 2 times sqrt 13

2nd Step: 6 times sqrt 2 + sqrt 2 + sqrt 13 times sqrt 13

Answer: 7 times sqrt 2 + 13

I was told that wasn't right either, so where did I go wrong and how do I solve this?

 

[galactus]

\(\displaystyle \L\\\sqrt{a^{5}b^{6}}=(a^{5}b^{6})^{\frac{1}{2}}=a^{\frac{5}{2}}b^{3}\)

\(\displaystyle \L\\(\sqrt{72}+\sqrt{26})\sqrt{13}=6\sqrt{26}+13\sqrt{2}\)

 

[Guest]

Thank you! It's great I have the answer, but can someone please show me how to solve them, especially the first problem?

\(\displaystyle sqrt(a^5b^6)\)

 

[stapel]

...can someone please show me how to solve them...?

What's wrong with the simplifications you've already been given? (Naturally, since these aren't equations, there is nothing to "solve", so there are no "solutions".)

Thank you.

Eliz.