\(\displaystyle \mbox{Simplify }\, \sqrt[5]{\strut \dfrac{27x^2}{y^3}\,}\, \cdot\, \sqrt[5]{\strut \dfrac{9x^6}{y^4}\,}\)
I combined the two radicals and got the root of 5((3^5)*(x^8) all over y^7)
Do you perhaps mean "the fifth root of"...? Because there is no way to convert the original fifth-roots to get a square root, and there is no way to get a five inside that root.
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In other words, by "the root of 5((3^5)*(x^8) all over y^7)", did you actually mean the following:
. . . . .5th-rt[ (3^5 x^8) / y^7 ]
...which typesets as:
. . . . .\(\displaystyle \sqrt[5]{\strut \dfrac{3^5\, x^8}{y^7}\,}\)
Kindly please reply with confirmation or else corrections.
i could pull out a 3 and an x but wouldn't know what to do after that?
Assuming I guessed correctly what you meant for the radical, I will guess that, by the above, you mean the following:
. . . . .\(\displaystyle \sqrt[5]{\strut \dfrac{3^5\, x^5\, x^3}{y^5\, y^2}\,}\,=\, \sqrt[5]{\strut 3^5\, x^5\,}\, \sqrt[5]{\strut \dfrac{x^3}{y^5\, y^2}\,}\,=\, (3)\, (x)\, \sqrt[5]{\strut \dfrac{x^3}{y^5\, y^2}\,}\)
If so, you're correct, as far has you've gone. But why did you stop there?
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