Simplify ((2/3) d^7)^4 ((9/2) d^4)^2

klettanator said:
\(\displaystyle \mbox{Simplify }\, \left(\frac{2}{3}\,d^7\right)^4\, \left(\frac{9}{2}\,d^4\right)^2\)
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What have you tried? How far have you gotten? Where are you stuck?

Please be complete. Thank you! :D

Eliz.
 
Re: can someone show me how to answer this?

i can get the right exponents and stuff.. i just get confused when i have to multiply or add or whatever to the fractions
 
Re: can someone show me how to answer this?

\(\displaystyle = (\frac{2}{3})^4 \cdot (d^7)^4 \cdot (\frac{9}{2})^2 \cdot (d^4)^2\)

\(\displaystyle = (\frac{2}{3})^4 \cdot (\frac{9}{2})^2 \cdot (d^4)^2 \cdot (d^7)^4\)

Now continue...
 
Re: can someone show me how to answer this?

\(\displaystyle = (\frac{2}{3})^4 \cdot (d^7)^4 \cdot (\frac{9}{2})^2 \cdot (d^4)^2\)

\(\displaystyle = (\frac{2}{3})^4 \cdot (\frac{9}{2}) \cdot (d^4)^2 \cdot (d^7)^4\)

\(\displaystyle = (\frac{2^4}{3^4}) \cdot (\frac{9^2}{2^2}) \cdot (d^4)^2 \cdot (d^7)^4\)

How about now....
 
Re: can someone show me how to answer this?

klettanator said:
how do i multiply fractions together?
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Are you serious?! (a/b) * (c/d) = (a*c) / (b*d).

If fractions "frighten" you as they appear in your problem,
start by: let a = 2/3 and b = 9/2; that'll make expression = (a^1 d^7)^4 (b^1 d^4)^2 ;
complete the work, then substitute back in; kapish?
 
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