Simplifing Rational Expressions - (3z^2+z)/(18z+6)

Deo3560

New member
Joined
Jul 30, 2010
Messages
23
Ok, I've been stuck on this problem for a while now, unable to find out the reason behind the answer...

The Question is:

(3z^2+z)
(18z+6)

The Answer is:

z
6

The thing I dont understand, is where does the z added to the numerator and the 6 added to the denominator go, in all the calculators I've seen it just dissapears.

Please Help, I would greatly appreciate if you could show me the work so I can understand it for future purposes.

Thanks,
~~~Deo3560~~~
 
Oh, I can't believe I didnt see that, I was trying to eliminate it like this:

(3*z*z+z)
(3*3*2*z+6)

should have done this,

(z(3z+1))
(6(3z+1))

then cancel it out from there.
 
Factor z from the top and 6 from the bottom:

\(\displaystyle \frac{z(3z+1)}{6(3z+1)}=\frac{z}{6}\)

See now?. The 3z+1 cancels. Nothing just disappears for no reason.
 
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