simplified (5a^2/3)(4a^3/2) to get 659a (is that right?)

awesome_m

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Aug 14, 2008
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i have to simplify this equation:
(5a^2/3)(4a^3/2)

i multiplied 5x4=20
i added 3/2+2/3=13/6
i got 20a^13/6= 659a

is it right? thank you!
 
Re: could someone tell me if this is right?

(5a^2/3)(4a^3/2) means \(\displaystyle \frac{5a^2}{3}\cdot \frac{4a^3}{2}\),
Or is it (5a^(2/3))(4a^(3/2)) which means \(\displaystyle (5a^\frac{2}{3})(4a^\frac{3}{2})\)?

If the latter then you are partially right. The problem becomes
\(\displaystyle 5\cdot 4 \cdot a^\frac{2}{3} \cdot a^\frac{3}{2}\)

Remember the rule \(\displaystyle a^x \cdot a^y = a^{x+y}\)
 
Re: could someone tell me if this is right?

awesome_m said:
i have to simplify this equation:
(5a^2/3)(4a^3/2)

i multiplied 5x4=20
i added 3/2+2/3=13/6
i got 20a^13/6= 659a It isn't \(\displaystyle 20^{\frac{13}{6}}\). It's \(\displaystyle 20a^{\frac{13}{6}}\)
is it right? thank you!

Final answer: \(\displaystyle 20a^{\frac{13}{6}}\), or \(\displaystyle 20\sqrt[6]{a^{13}}\), or \(\displaystyle 20a^2\sqrt[6]{a}\)
 
Re: could someone tell me if this is right?

Previous post should be \(\displaystyle 20a^2\sqrt[6]{a}\)
 
Re: could someone tell me if this is right?

Loren said:
Previous post should be \(\displaystyle 20a^2\sqrt[6]{a}\)

Thanks, Loren. You're a "diamond in the rough" My post has been corrected to reflect your keen observation.
 
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