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Simplification without a calculator: (2,1x+0,7x)+0,7 2). 3,45ab-1,76ab+2,31ab 3). 7,
- Thread starter Cal
- Start date
Okay, so it looks like you're using a slightly different notation than I'm used to seeing, wherein you've used the comma (,) to indicate the separation between the whole number portion of a number and the fractional portion. I'm used to seeing the period (.) used for the same, and the comma reserved for the thousands separator. Assuming that's correct, the way I'd go about solving these problems is to think about what they really mean. Clearly the abstract symbolic notation isn't working for you, so let's make it more concrete and "real."
For the purposes of these problems, let's temporarily replace the symbol x with the phrase "litres of petrol." If we then rewrite the part of first problem in parentheses out in words, we have "2.1 liters of petrol plus 0.7 litres of petrol." How many litres of petrol would you have total? Now remember to re-substitute the symbol x for the phrase. What do you have then? Now let's add the number, which has no units attached. We'll have something like (some number)x + 0.7. From there, can you maybe simplify the expression a bit further? Is there some common factor that these two numbers have? For instance, if you had 0.6x + 0.3, you could factor that into 0.3(2x + 1).
Go ahead and give these problems another try. If you get stuck again, that's alright, but when you reply back please include all the work you've done on these problems, even the parts you know for sure are wrong. Thank you.
For the purposes of these problems, let's temporarily replace the symbol x with the phrase "litres of petrol." If we then rewrite the part of first problem in parentheses out in words, we have "2.1 liters of petrol plus 0.7 litres of petrol." How many litres of petrol would you have total? Now remember to re-substitute the symbol x for the phrase. What do you have then? Now let's add the number, which has no units attached. We'll have something like (some number)x + 0.7. From there, can you maybe simplify the expression a bit further? Is there some common factor that these two numbers have? For instance, if you had 0.6x + 0.3, you could factor that into 0.3(2x + 1).
Go ahead and give these problems another try. If you get stuck again, that's alright, but when you reply back please include all the work you've done on these problems, even the parts you know for sure are wrong. Thank you.
HallsofIvy
Elite Member
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- Jan 27, 2012
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(2,1x+ 0,7x)= (2,1+ 0,7)x and 2,1+ 0,7= 2,8.Hi All,I'm in dire need of help. I do i solve the below: It says "Simplify without using a calculator" 1). (2,1x+0,7x)+0,7
3,45ab- 1,756ab+ 2,31ab= (3,45- 1,756+ 2,31)ab.2). 3,45ab-1,76ab+2,31ab
3,45+ 2.31= 5,76 so this is (5,76- 1,756)ab= 4,004ab.
I presume the "x3" is x^3, "x cubed". The only "simplification" possible is to add the two numbers: 8+ 0,5= 8,5. So this is 7,5x^3+ 8,5.3). 7,5x3+8+0,5