Simplification of equation

[Cortes]

Hi there,

I need some help with the simplification of this equation:
http://latex.codecogs.com/gif.latex?\frac{6^{2x+3}}{3%289^{x-1}%29-3^{2x+1}}

Is it a mathematical faux pas to divide 3 to all terms to simplify? Would it be required to draw out a common term and exponent and cancel out, or is that move not possible?
I don't entirely know where to begin.

Many thanks.

 

[daon2]

You could divide everything by 3, but that might not help much.

Maybe this will get you started:

\(\displaystyle \displaystyle \frac{6^{2x+3}}{3(9^{x-1})-3^{2x+1}} = \frac{(2\cdot 3)^{2x+3}}{3(3^2)^{x-1}-3^{2x+1}}= \frac{2^{2x+3}\cdot 3^{2x+3}}{3^{2(x-1)+1}-3^{2x+1}}\)

 

[mmm4444bot]

I need some help with the simplification of this equation

Your expression is not an equation. Equations always contain an equals sign. Does your post contain typographical error(s)?