simple algebra?

[maeveoneill]

If 2^x = 2(16^12) + 2(8^16), what is the value of x?

This is how I tried to do it, but when I subbed in my value for x, it didnt work:

2^x = 2(16^12) + 2(8^16)
= 2(2^48) + 2(2^48)
= 4(2^48)
= 2^2(2^48)
x = 2 . 48
= 96

HELP CAUSE THIS DOESNT WORK! THANK YOU!!

 

[soroban]

Hello, maeveoneill!

A simple error . . . just before the punchline . . .

If $\displaystyle 2^x \:= \:2(16^{12})\,+\,2(8^{16})$, what is the value of $\displaystyle x$?

This is how I tried to do it . . .


$\displaystyle 2^x \:= \:2(16^{12})\,+\, 2(8^{16})$
\(\displaystyle \;\;\;\;=\:2(2^:48})\,+\,2(2^{48})\)
$\displaystyle \;\;\;\;= \:4(2^{48})$
$\displaystyle \;\;\;\;= \:2^2(2^{48})$
$\displaystyle \;\;x\:=\:2\cdot48\;\;$ . . . no
$\displaystyle \;\;\;\;=\:96$

You had: \(\displaystyle \,2^x\:=\2^2)(2^{48})\quad\Rightarrow\quad 2^{50}\)

 

[maeveoneill]

SMART! THANKS.. so i was on the right track!