ejkaminsky said:Ina trapezoid the parallel sides are in the ratio k:1 where k>1. The line segment joining the midpoints of the non-parallel sides divides the trapezoid into two regions whose areas are in the ratio 5:2. What is the value of k?
A) 12
B)5/2
C)13
D)25/5
E)7
Let a = the short parallel side and ka = the long side.
Then, a(k+1)/2 = the median (the average of the two parallel sides).
The larger area A1 = [ka + a(k+1)/2]/2 = a(3k+1)/4
The smaller area is A2 = [a + a((k+1)]/2
Dividing a1 by a2 yields (3k+1)/(k+3) = 5/2
I suspect you can take it from here.
Hi there,
I'm having trouble with a similar question and was wondering you can point me in the right direction. I have a trapzoid with the one side angle at 67 deg and the other at 72 deg. The height of the trapezoid is 40. Is it possible with this amount of information to calculate the ratio of the bases, assuming 'a' is the short base and 'ka' is the longer of the two bases?
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