Hey everyone!
I need to prove or disprove the following:
Now, since I know they are 10x10 and their rank is 2 then each one has eigen value 0 with a geometric multiplicity of 8. Then we can get to a conclusion that each of the matrices have the same eigenvalues.
Eigenvalues: (a.m. = algebraic multiplicity ; g.m. = geometric multiplicity)
Also, their rank is the same, their determinant (0) and their trace (7).
So I cannot disprove them being similar but this does not prove they are similar either!
Please help!
I need to prove or disprove the following:
If two matrices A and B are 10x10 over \(\displaystyle \mathbb{R}\), their rank is 2 and the numbers 3 and 4 appear in their eigenvalues, then A and B are similar.
Now, since I know they are 10x10 and their rank is 2 then each one has eigen value 0 with a geometric multiplicity of 8. Then we can get to a conclusion that each of the matrices have the same eigenvalues.
Eigenvalues: (a.m. = algebraic multiplicity ; g.m. = geometric multiplicity)
- 0 (a.m.=8, g.m.=8)[/*:m:55ltqq4f]
- 3 (a.m.=1, g.m.=1)[/*:m:55ltqq4f]
- 4 (a.m.=1, g.m.=1)[/*:m:55ltqq4f]
Also, their rank is the same, their determinant (0) and their trace (7).
So I cannot disprove them being similar but this does not prove they are similar either!
Please help!