Side side angle solutions

smsmith

New member
Joined
Sep 15, 2006
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18
I could use a little help my text book is confusing me.

This is from one of the examples. A=42 degrees, b=12, a=22.

Iknow that a/sinA= b/sinB= c/sinC. my problem is in solving for Sin B my result is.

12(sin(42)/22)=.3649=sinB but how do I get the anle of sin B from this result?
Any help would be appreciated. I am sure I know this but the textbook just goes from 12(sin42)/22)=21.41 degrees without any further explanation and it is crossing my wires.
 
are you familiar with the inverse sine function on your calculator?

sin<sup>-1</sup>[12sin(42)/22] = 21.41
 
Thanks, I figured that out a minute ago. But, thank you for responding I appreciate the help.
 
When I use the inverse sin on this I get 21.5532 my textbook gives 21.41? what could account for this I have entered it repeatidly and keep getting 21.55.
:?
 
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