Showing x-y is factor of x^3 - 2x^2y -5xy^2 + 6y^3

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popcorn123

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Generalized:

Show that () is a factor of <>. Factor fully.

() = x - y
<>= x^3 - 2x^2y -5xy^2 + 6y^3
 
popcorn123 said:
Generalized:

Show that () is a factor of <>. Factor fully.

() = x - y
<>= x^3 - 2x^2y -5xy^2 + 6y^3
Click to expand...
So... you did the polynomial long division and... then what?

Please be complete. Thank you! ;)
 
stapel said:
So... you did the polynomial long division and... then what?

Please be complete. Thank you! ;)
Click to expand...

Forget it - you guys don't wanna help. If you're spending your whole life on this forum *​(Geek Alert) - then at least help someone instead of trying to weasel the answer out of them. The only reason I asked is because I did NOT KNOW what to do - I was confused and had no idea how to move forward - I thought seeing someone else's solutions might give me ideas on how to approach problems such like these.

But forget it. I'll just ask my teacher instead. At least he knows what he's doing.
 
popcorn123 said:
Forget it - you guys don't wanna help.
Click to expand...
I'm sorry you view leading questions, suggestions, links, and helps to be "not wanting to help". Perhaps you could clarify what you do mean by "help"?

When you reply, please clarify what you mean by having no idea what to do (even in light of the replies you've received). Are you needing lesson instruction (that is, explanations, with worked examples) for the topics at hand, along with the likely topics of the previous chapter or two in your textbook?

Please be specific. Thank you! ;)
 
stapel said:
I'm sorry you view leading questions, suggestions, links, and helps to be "not wanting to help". Perhaps you could clarify what you do mean by "help"?

When you reply, please clarify what you mean by having no idea what to do (even in light of the replies you've received). Are you needing lesson instruction (that is, explanations, with worked examples) for the topics at hand, along with the likely topics of the previous chapter or two in your textbook?

Please be specific. Thank you! ;)
Click to expand...

I don't think you want "help".....you want us to do the problems for you. Our questions TO YOU are designed to help you think through the solutions for yourself.

Believe me, it would be far easier for us to just give you the "final answer,".....but that is not why we are here.
 
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