Showing proof of a tangent line (My work is included here )

Calculista222

New member
Joined
Nov 6, 2010
Messages
7
x[sup:8xddvpac]2[/sup:8xddvpac]+y[sup:8xddvpac]2[/sup:8xddvpac] = 1


2x + 2y (dy/dx) = 0


dy/dx = -x/y


And.. stuck.

Any ideas?
 
Re: Showing proof of a tangent line (My work is included her

Calculista222 said:
x[sup:2s35ykc4]2[/sup:2s35ykc4]+y[sup:2s35ykc4]2[/sup:2s35ykc4] = 1


2x + 2y (dy/dx) = 0


dy/dx = -x/y


And.. stuck.

Any ideas?

Now you have slope of the tangent line [at (x[sub:2s35ykc4]o[/sub:2s35ykc4],y[sub:2s35ykc4]o[/sub:2s35ykc4])]- and you know that the line has to pass through (x[sub:2s35ykc4]o[/sub:2s35ykc4],y[sub:2s35ykc4]o[/sub:2s35ykc4])

Write the equation of the line.
 
Re: Showing proof of a tangent line (My work is included her

y = -1/2 + 1


Is that the correct answer? How I got -1/2 as the slope is by plugging in a random point into the formula of -x/y
 
Re: Showing proof of a tangent line (My work is included her

Calculista222 said:
y = -1/2 + 1


Is that the correct answer? How I got -1/2 as the slope is by plugging in a random point into the formula of -x/y

No

Equation of a line with slope = m and passing through (x[sub:2vzird57]1[/sub:2vzird57],y[sub:2vzird57]1[/sub:2vzird57]) is

(y - y[sub:2vzird57]1[/sub:2vzird57]) = m * (x - x[sub:2vzird57]1[/sub:2vzird57])

The answer is already given to you - you need to prove it.
 
Top