patter2809
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- Joined
- Mar 29, 2013
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- 17
Set S defined as { (x,y)t | y =/> x2 }. Required to show that S is convex.
Let u = (x1,y1) with u E S, and v = (x2,y2) with v E S. Need to show that any w, with w = a u + (1-a) v (0</= a </= 1) E S.
w = (w1,w2) with,
w2 =/> w1
(a y1 + (1-a) y2) =/> (a x1 + (1-a) x2)2
a y1 + (1-a)y2 =/>a2 x12 + 2 (1-a) a x1x2 + (1-a)2 x22
Since 0 </= a </= 1, a2 </= a.
y1 =/> x12 since u E S which implies ay1 =/> a2x12, and since v E S, (1-a)y2 =/> (1-a)2 x22.
But this still leaves the 2 (1-a) a x1x2 ?
Thanks in advance!
Let u = (x1,y1) with u E S, and v = (x2,y2) with v E S. Need to show that any w, with w = a u + (1-a) v (0</= a </= 1) E S.
w = (w1,w2) with,
w2 =/> w1
(a y1 + (1-a) y2) =/> (a x1 + (1-a) x2)2
a y1 + (1-a)y2 =/>a2 x12 + 2 (1-a) a x1x2 + (1-a)2 x22
Since 0 </= a </= 1, a2 </= a.
y1 =/> x12 since u E S which implies ay1 =/> a2x12, and since v E S, (1-a)y2 =/> (1-a)2 x22.
But this still leaves the 2 (1-a) a x1x2 ?
Thanks in advance!