maeveoneill
Junior Member
- Joined
- Sep 24, 2005
- Messages
- 93
There is an example in my calculus textbook that goes as follows:
Show tha the sequence an= n/(n^2 +1) is decreasing
Solution: We must show that an+1 < an, that is,
n + 1/ [(n +1)^2 +1) < n/ n^2 +1
The inequality is equivalent to the one we get by cross-multiplication:
n + 1/ [(n +1)^2 +1) < n/ n^2 +1 <=> (n+1)(n^2 +1) <n[(n+1)^2 +1]
. <=> n^3 + n^2 +n + 1 < n^3 +2n^2 +2n
. <=> 1 < n^2 +n
Since n > or equal 1, we know that the inequality n^2 +n >1 is true. Therefore an+1 <an and so {an} is decreasing.
I don't understand how this proves that the sequence is decreasing.. or why you would use the cross multiplication method. could you not just prove it using examples of direct substition.. anywyas if someone could explain how this means that the function is decreasing.. especially with regards to the last statement that would be wonderful. Thank youu..
Show tha the sequence an= n/(n^2 +1) is decreasing
Solution: We must show that an+1 < an, that is,
n + 1/ [(n +1)^2 +1) < n/ n^2 +1
The inequality is equivalent to the one we get by cross-multiplication:
n + 1/ [(n +1)^2 +1) < n/ n^2 +1 <=> (n+1)(n^2 +1) <n[(n+1)^2 +1]
. <=> n^3 + n^2 +n + 1 < n^3 +2n^2 +2n
. <=> 1 < n^2 +n
Since n > or equal 1, we know that the inequality n^2 +n >1 is true. Therefore an+1 <an and so {an} is decreasing.
I don't understand how this proves that the sequence is decreasing.. or why you would use the cross multiplication method. could you not just prove it using examples of direct substition.. anywyas if someone could explain how this means that the function is decreasing.. especially with regards to the last statement that would be wonderful. Thank youu..