Question:
Show that g(x)=(x/2)+ (1/x) has a unique fixed point in the interval [1,2] using a fixed point theorem.
Do not approximate the fixed point. Verify all conditions.
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My work so far:
We see on the graph that theres an intersection with g(x) and y=x and its a unique fixed point because a fixed point of g(x) are solutions of g(x)=x.
g(1.4142136)= 1.4142136
----------------------------
My problem:
Not sure how to prove it, i think ive somewhat have the start, maybe, but have no idea on how to do the other part of the fixed point theorem.
Please Help!!!! thanks in advance
Show that g(x)=(x/2)+ (1/x) has a unique fixed point in the interval [1,2] using a fixed point theorem.
Do not approximate the fixed point. Verify all conditions.
---------------------------
My work so far:
We see on the graph that theres an intersection with g(x) and y=x and its a unique fixed point because a fixed point of g(x) are solutions of g(x)=x.
g(1.4142136)= 1.4142136
----------------------------
My problem:
Not sure how to prove it, i think ive somewhat have the start, maybe, but have no idea on how to do the other part of the fixed point theorem.
Please Help!!!! thanks in advance
