show deriv of M(lambda) = 2(n bar)L is delta(lambda) = ....

[nvr2low]

im working on a problem and it doesnt make much sense. im not familiar with how to type out a problem on the computer so i will try to make it easy to follow.

Im supposed to show that the derivative of this M(lambda)=2(n bar)(L) differentiates to

delta(lambda)=((lambda squared)(delta M))/((2 n bar L)(1-(lambda/n bar)(dn bar/dlabda))

I will try to take a screen shot and post it so its a little easier to follow. I dont see how you can take a small equation like that with no exponents and turn it into something so much bigger with exponents by taking the derivative.

 

[nvr2low]

Re: help please

no ideas, or is it too hard to understand typed out?

 

[stapel]

im not familiar with how to type out a problem on the computer...

Try reading the articles in the "formatting" links you saw in the "Read Before Posting" thread you read before posting. :wink:

Im supposed to show that...M(lambda)=2(n bar)(L) differentiates to

delta(lambda)=((lambda squared)(delta M))/((2 n bar L)(1-(lambda/n bar)(dn bar/dlabda))

Are you given any information about \(\displaystyle \lambda\), "n bar", or L? Are you told with respect to what you're supposed to differentiate?

Thank you!

 

[nvr2low]

Im given the two equations at the begging and that L=M((lambda)/(2xnbar))

so i subbed that into the original equation, but when the simplifies i end up with Mxlambda=Mxlambda.

its been about 6 years since i have done any calc so this one is killing me.

 

[nvr2low]

here is a couple screen shots of the problem, maybe it will clear things up a little.