SHELL METHOD

Ryan Rigdon

Junior Member
Joined
Jun 10, 2010
Messages
246
i posted this problem earlier but deleted it. i did it again and i am confident that this time its right. what do you think. :D
 

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i just turned in my quiz and got the above problem correct. and scored a 100 on my quiz.
 
Disc: Revolved around x = 0 (yaxis).\displaystyle Disc: \ Revolved \ around \ x \ = \ 0 \ (y-axis).

π01[((y+9)/10)2(y2)2]dy+π90[(y+9)/10]2dy = 47π15\displaystyle \pi\int_{0}^{1}[((y+9)/10)^2-(y^2)^2]dy+\pi\int_{-9}^{0}[(y+9)/10]^2dy \ = \ \frac{47\pi}{15}

Shell: Revolved around x = 0 (yaxis).\displaystyle Shell: \ Revolved \ around \ x \ = \ 0 \ (y-axis).

2π01x[x1/2(10x9)]dx = 47π15\displaystyle 2\pi\int_{0}^{1}x[x^{1/2}-(10x-9)]dx \ = \ \frac{47\pi}{15}
 
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