Apologies if this is the incorrect forum for this question..
I would really appreciate some help in proofing the following.
(A ^ B)' ^ B = B ^ A'
Reads as complement of A intersect B , intersected with B, is equal to B intersect A complement.
See the quote above. It is a lot more readable is it not?Apologies if this is the incorrect forum for this question..
I would really appreciate some help in proofing the following.
\(\displaystyle (A \cap B)^c\cap B = B \cap A^c\)
Reads as complement of A intersect B , intersected with B, is equal to B intersect A complement.
Try using the standard method of "element-chasing".I would really appreciate some help in proofing the following.
(A ^ B)' ^ B = B ^ A'
Reads as complement of A intersect B , intersected with B, is equal to B intersect A complement.