Hello friends:
Can anyone solve my below mentioned maths problem...
Consider a set with 256 numbers (May be integer ,real , etc).
First step:
1) From the set of 256 numbers, Pick any 3 numbers
2) Apply some calculation on the picked numbers to generate 2 numbers (Converting 3 numbers to 2 numbers).
3) The 2 Numbers should be part of the original set
Second step:
To reverse the process, i.e, Converting this 2 Numbers to the original 3 Numbers back.
1) Take the same 2 numbers
2) Apply some calculation on the these numbers and get back the original numbers (3 numbers) in the same sequence.
EXAMPLE:
(1,2,3,4....256) - Original Set
(2,55,255) - Random pick from the above set
(75,155) - Calculating with formula from the above 3 numbers and derive 2 numbers which will pe part of the original set.
(2,55,255) - Doing reverse calculation of the above 2 numbers and derive the same 3 numbers.
I would be glad if someone can get an answer and send it to me [e-mail address deleted for security].
Thanks and regards,
Srikanth
Can anyone solve my below mentioned maths problem...
Consider a set with 256 numbers (May be integer ,real , etc).
First step:
1) From the set of 256 numbers, Pick any 3 numbers
2) Apply some calculation on the picked numbers to generate 2 numbers (Converting 3 numbers to 2 numbers).
3) The 2 Numbers should be part of the original set
Second step:
To reverse the process, i.e, Converting this 2 Numbers to the original 3 Numbers back.
1) Take the same 2 numbers
2) Apply some calculation on the these numbers and get back the original numbers (3 numbers) in the same sequence.
EXAMPLE:
(1,2,3,4....256) - Original Set
(2,55,255) - Random pick from the above set
(75,155) - Calculating with formula from the above 3 numbers and derive 2 numbers which will pe part of the original set.
(2,55,255) - Doing reverse calculation of the above 2 numbers and derive the same 3 numbers.
I would be glad if someone can get an answer and send it to me [e-mail address deleted for security].
Thanks and regards,
Srikanth