set of all prime numbers that can divide two successive integers

matematicar

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Nov 3, 2016
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Hello everybody, again I'm stuck in at the middle and don't know how to proceed with the task:

Determine with the proof the set of all prime numbers that can divide two successive integers of the form n^2 + 3.

My work so far (I hope that is correct):

if m is an positive integer then m is divisible by n^2 + 3 and (n+1)^2 + 3

it means that m divides the difference of the terms which is 2n + 1
and
it means that m divides twice the sum of the terms which is (2n+1)^2 + 13

Now I got that m is divisible by 13 (which is a prime number).

But now my struggle is, is that the only prime? Why am I asked for all prime number that can divide two successive integers of the form? Can somebody help me with that part?
Thank you so much!
 
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