Series: f(x)=10x^2 arctan(x^6) is sum[n=0,infty](c_n)(x^n)

matt3D

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Oct 29, 2008
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Hello, I have a problem that says:

The function

84663dcbc5f4b6d7536cc506b51b6c1.png


is represented as a power series

8bdd71cc91af1c7f7aa5c2ef4b77461.png


What is the lowest term with a nonzero coefficient and find the radius of convergence R of the series.

Okay so, I know that:

\(\displaystyle 10x^2\sum_{n=0}^\infty(-1)^n \frac{(x^6)^{2n+1}}{2n+1}\)

The problem is I'm not sure why I would use that and how I would go through the rest of the problem, my teacher went over a similar problem and I didn't understand what she meant. I know that the radius of convergence is 1 since \(\displaystyle \| x^6 \| < 1\). I'm not sure why there are two absolute bars, I only wanted one set but I couldn't get latex to just put one on each side... :mrgreen:

Thanks,
Matt
 
matt3D said:
Hello, I have a problem that says:

The function

84663dcbc5f4b6d7536cc506b51b6c1.png


is represented as a power series

8bdd71cc91af1c7f7aa5c2ef4b77461.png


What is the lowest term with a nonzero coefficient and find the radius of convergence R of the series.

Okay so, I know that:

\(\displaystyle 10x^2\sum_{n=0}^\infty(-1)^n \frac{(x^6)^{2n+1}}{2n+1}\)

The problem is I'm not sure why I would use that and how I would go through the rest of the problem, my teacher went over a similar problem and I didn't understand what she meant. I know that the radius of convergence is 1 since \(\displaystyle \| x^6 \| < 1\). I'm not sure why there are two absolute bars, I only wanted one set but I couldn't get latex to just put one on each side... :mrgreen:

Thanks,
Matt

Have you worked with Taylor series?

You are looking at Taylor series expansion of "arctan" function.
 
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