sequence
- Thread starter mario99
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a1 means "what would you get from an (expression above) when n= 1"
Please show us what you have tried and exactly where you are stuck.
Please follow the rules of posting in this forum, as enunciated at:
Please share your work/thoughts about this problem.
Thank you very much Subhotosh Khan for helping me.
\(\displaystyle a_1 = \frac{2(1) - 1}{1^2}\)
Dr.Peterson
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Keep going! What is the value of [imath]a_1[/imath]? Of [imath]a_2, a_3, ...[/imath]?
\(\displaystyle a_1 = \frac{2(1) - 1}{1^2} = 1\)
\(\displaystyle a_2 = \frac{2(2) - 1}{2^2} = \frac{3}{4}\)
\(\displaystyle a_3 = \frac{2(3) - 1}{3^2} = \frac{5}{9}\)
\(\displaystyle a_4 = \frac{2(4) - 1}{4^2} = \frac{7}{16}\)
\(\displaystyle a_5 = \frac{2(5) - 1}{5^2} = \frac{9}{25}\)
\(\displaystyle a_6 = \frac{2(6) - 1}{6^2} = \frac{11}{36}\)
\(\displaystyle a_2 = \frac{2(2) - 1}{2^2} = \frac{3}{4}\)
\(\displaystyle a_3 = \frac{2(3) - 1}{3^2} = \frac{5}{9}\)
\(\displaystyle a_4 = \frac{2(4) - 1}{4^2} = \frac{7}{16}\)
\(\displaystyle a_5 = \frac{2(5) - 1}{5^2} = \frac{9}{25}\)
\(\displaystyle a_6 = \frac{2(6) - 1}{6^2} = \frac{11}{36}\)