Seeking help with 3- x-1/2 = x-3/3
- Thread starter hootie618
- Start date
- Joined
- Feb 4, 2004
- Messages
- 16,582
Your formatting is ambiguous. Do you mean any of the following?hootie618 said:
. . . . .3 - x - (1/2) = x - (3/3)
. . . . .3 - x - (1/2) = (x - 3) / 3
. . . . .3 - (x - 1) / 2 = x - (3/3)
. . . . .3 - (x - 1) / 2 = (x - 3) / 3
Or something else?
Also, what were the instructions?
When you reply, please show everything you have tried so far, even if you think it is wrong.
Thank you.
Eliz.
- Joined
- Feb 4, 2004
- Messages
- 16,582
Lacking an actual question, there is no sure way of providing an answer. You might want to point out to your instructor that the assignment only listed exercises, but never said what to do with any of them.hootie618 said:
What do you mean by "doing fractional equations"? (And do you mean "equations", "expressions", or "functions"?) Are you finding domains? Ranges? Finding asymptotes? Graphing? Solving? Or something else?hootie618 said:
When you reply, please show everything you have tried so far, even if you think it is wrong.
Thank you.
Eliz.
- Joined
- Feb 4, 2004
- Messages
- 16,582
Ah; so there were instructions, though they are odd ones. (One might "simplify" to find the lowest common denominator. One customarily just plain "solves"; the denominators are typically irrelevant, unless the solution is a fraction. I'm not sure what your book means by that.)hootie618 said:
To solve, a good first step might be to multiply through by the LCM, thus getting rid of the fractions. Then solve the resulting linear equation by the usual methods.
When you reply, please show everything you have tried so far, even if you think it is wrong.
Thank you.
Eliz.