Section 3 Roots of Equations

[sarahlee]

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3) Solve [FONT=MathJax_Main]3[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]3[/FONT][FONT=MathJax_Main]0[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]2[/FONT][FONT=MathJax_Main]−[/FONT][FONT=MathJax_Main]124[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]−[/FONT][FONT=MathJax_Main]96[/FONT][FONT=MathJax_Main]=[/FONT][FONT=MathJax_Main]0[/FONT]3x30x2−124x−96=0.
The roots in ascending order (correct to 3 decimal places) are , and .

solved

 

[Dr.Peterson]

Section 3 Roots of Equations

3) Solve [FONT=MathJax_Main]3[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]3[/FONT][FONT=MathJax_Main]0[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]2[/FONT][FONT=MathJax_Main]−[/FONT][FONT=MathJax_Main]124[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]−[/FONT][FONT=MathJax_Main]96[/FONT][FONT=MathJax_Main]=[/FONT][FONT=MathJax_Main]0[/FONT]3x30x2−124x−96=0. The roots in ascending order (correct to 3 decimal places) are , and .

This one really has me baffled. I suppose it may be meant to be 3x(30x²−12)/(4x−96)=0, but that isn't a very interesting problem.

Please resubmit, typing the problem out carefully. But only do so if you also show work or explain where you need help.

 

[mmm4444bot]

solved

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