second derivative of e^x (x^2+2x+1) (I get e^x (x^2+6x+7))

mdem1234

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Apr 6, 2009
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15
Hey guys,

can anyone let me know if I've done this correctly..

The second derivative of e^x(x^2+2x+1)
is
e^x(x^2+6x+7)

Thanks for your time :D
 
Re: second derivative

f[x]= e^u
u=x^3+2x^2+x

f ' = e^u u'

f ' ' = e^u u' ' + u' e^u u'
f ' ' =e^u [ (u')^2+u '' ]

u'= 3x^2+4x +1
[u']^2= 9x^4 +24x^3 + 22x^2 +8x+1
u '' =6x+4

[u']^2 + u''= 9x^4+24x^3+22x^2+14x +5
f ' ' [x] = [9x^4+24x^3+22x^2+14x+5] e ^(x^3+2x^2+x) answer

please check the math
Arthur
 
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