Becky4paws
Junior Member
- Joined
- Feb 15, 2006
- Messages
- 63
f(x) = 2x(x+4)^3
f'(x) = [(x+4)^3(2)] + [2x(3)(x+4)^2]
f'(x) = (x+4)^2(8x+8)
Assuming that is correct, the second derivative:
f"(x) = 8(x+4)^2 + 2(x+4)(x+1)
f"(x) = 8(x+4)[(x+4) + 2(x+1)]
f"(x) = 8x(x+4)(3x+6)
f"(x) = 24(x+1)(x+2)
I'm crossing my fingers, I think it may actually be correct
f'(x) = [(x+4)^3(2)] + [2x(3)(x+4)^2]
f'(x) = (x+4)^2(8x+8)
Assuming that is correct, the second derivative:
f"(x) = 8(x+4)^2 + 2(x+4)(x+1)
f"(x) = 8(x+4)[(x+4) + 2(x+1)]
f"(x) = 8x(x+4)(3x+6)
f"(x) = 24(x+1)(x+2)
I'm crossing my fingers, I think it may actually be correct