I am having trouble solving the following: 2^x = 4 the solution set is ( )
S soprano New member Joined Jan 29, 2010 Messages 12 May 4, 2010 #1 I am having trouble solving the following: 2^x = 4 the solution set is ( )
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 May 4, 2010 #2 If a^x = b, then x = log(b) / log(a)
D Deleted member 4993 Guest May 5, 2010 #3 soprano said: I am having trouble solving the following: 2^x = 4 the solution set is ( ) Click to expand... Or you can use the fact that 4 = 2[sup:3b87c55r]2[/sup:3b87c55r]
soprano said: I am having trouble solving the following: 2^x = 4 the solution set is ( ) Click to expand... Or you can use the fact that 4 = 2[sup:3b87c55r]2[/sup:3b87c55r]