SAT question about area and volume

garveym2

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Jul 11, 2007
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I am currently tutoring a student who is preparing for the SAT and I am hoping you can give me an explanation to a problem we are both stuck on:

The areas of the bottom, the side and the front of a rectangular box are r, s, and t square inches, respectively. What is the volume of the box, in cubic inches?

A. (rst)^3
B. (rst)^2
C. rst
D. square root of (rst)
E. third root of (rst)
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let the dimensions of the box be L, W, and H

V = rH

V = sL

V = tW

V<sup>3</sup> = (rH)(sL)(tW)

V<sup>3</sup> = (rst)(LWH)

V<sup>3</sup> = (rst)(V)

V<sup>2</sup> = rst

V = sqrt(rst)
 
V = LWH

LW = r [1]
LH = s [2]
WH = t [3]

[1] * [2] * [3]: L^2W^2H^2 = rst ; (LWH)^2 = rst ; LWH = sqrt(rst)
 
Among all the answers only sqrt(rst) has the same dimension as the Vume - hence that must be the answer.

In SAT, sometimes you have to find answer like above to be fast!!!
 
Hello, garveym2!

The areas of the bottom, the side and the front of a rectangular box
are \(\displaystyle r,\:s,\:\) and \(\displaystyle t\) square inches, respectively.
What is the volume of the box, in cubic inches?

\(\displaystyle A.\; (rst)^3\;\;\;\;B.\; (rst)^2\;\;\;C.\; rst\;\;\;D.\;\sqrt{rst}\;\;\;E.\;\sqrt[3]{rst}\)
Code:
. . . - - * - - - - - *
. . . - -/- - - - - -/|
. . . - / - - - - - / |H
. . . -/- - - - - -/- |
. . . * - - - - - * - *
. . . | - - - - - | -/
. . .H| - - - - - | /W
. . . | - - - - - |/
. . . * - - - - - *
. . . - - - L

We know that: \(\displaystyle \:V \;=\;LWH\)

\(\displaystyle \begin{array}{ccccc}\text{The bottom has area }r: & \;LW & = & r & \;[1]\\
\text{The side has area }s: & \;WH & = & s & \;[2]\\
\text{The front has area }t: & \;LH & = & t & \;[3]\end{array}\)

Multiply [1], [2] and [3]: \(\displaystyle \:(LW)(WH)(LH) \:=\:rst\;\;\Rightarrow\;\;L^2W^2H^2\:=\:rst\)

Take the square root: \(\displaystyle \:LWH \:=\:\sqrt{rst}\)

Therefore: \(\displaystyle \:V \:=\:\sqrt{rst}\)

 
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