Sampling distribution

[chengeto]

Suppose it is known that 18% of “Scratch and Win” lottery tickets are winners. It is known that whether
one ticket is a winner is independent of any other.


What is the 33rd percentile of the sampling distribution of pˆ ?



Attempt to solution :

In this formula l don't know what is SE how do l calculate for SE ?

 

[chrisr]

SE means the "Standard Error" of the mean, when dealing with sample means for "n" samples.

The standard deviation of the distribution of the sample means is given as the standard deviation of the entire population
divided by the square root of "n".

SE = sigma/{sqrt(n)} or (SD)/{sqrt(n)}.

You don't have sample information in the problem statement though.
Are you dealing with samples or the population?

What you've got there is P(win) = 0.18