Sample space: {A, B, C, D}... then P(B, C, D) = ??

[Navyguy]

Sample space: {A, B, C, D}

P(A) = 0.2, P(B) = 0.2, P(C) = 0.15, P(D) = 0.45

Then P(B, C, D) = _____

if you add the probabilities for B,C, and D, you get 0.80, this is my answer. Is this right? Thanks for checking my answer.

 

[tkhunny]

See, now you switched notation.

There is an easier way.

Pr(B,C,D) = 1 - Pr(A)

OK, these are too easy. Stop second guessing yourself.