Rubbish?

soroban

Elite Member
Joined
Jan 28, 2005
Messages
5,586
At another site, someone posted:

tan(A+B) = sin^2A - sin^2B/sin AcosA - sinBcos B


Someone asked him to use paretheses.
This was his response:


what rubbish is this??
cant you see the question clearly numerator and denominator are separated by '/' sign?

This was my reponse . . .


\(\displaystyle \text{Rubbish?}\)

\(\displaystyle Think\text{ before you dispay your attitude . . .}\)


\(\displaystyle \text{If you wanted: }\:x^2 + 3x - \frac{2}{x^2} - 4,\,\text{ how would you write it?}\)

\(\displaystyle \text{Probably: }\:x^2 + 3x - 2/x^2 - 4\;\hdots\text{ right?}\)

. . \(\displaystyle \text{(The numerator and denominator are }clearly\text{ separated by the "/".)}\)



\(\displaystyle \text{According to your system, }all\text{ of these would be written the same way:}\)

. . \(\displaystyle \begin{array}{ccc} x^2 + 3x - \dfrac{2}{x^2-4} & \Rightarrow & x^2 + 3x - 2/x^2-4 \\ \\ x^2 + \dfrac{3x-2}{x^2} - 4 & \Rightarrow & x^2 + 3x - 2/x^2-4 \\ \\ x^2 + \dfrac{3x-2}{x^2-4} & \Rightarrow & x^2 + 3x - 2/x^2-4 \\ \\ \dfrac{x^2+3x-2}{x^2} - 4 & \Rightarrow & x^2 + 3x - 2/x^2-4 \\ \\ \dfrac{x^2 + 3x - 2}{x^2-4} & \Rightarrow & x^2 + 3x - 2/x^2 - 4 \end{array}\)


\(\displaystyle \text{So, what do you plan to do about it?}\)
 


I continue to ponder multiple changes to our "Read Before Posting" page. The grouping-symbols issue would be discussed near the top, and your examples would make a nice demonstration there.

 
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