At another site, someone posted:
Someone asked him to use paretheses.
This was his response:
This was my reponse . . .
tan(A+B) = sin^2A - sin^2B/sin AcosA - sinBcos B
Someone asked him to use paretheses.
This was his response:
what rubbish is this??
cant you see the question clearly numerator and denominator are separated by '/' sign?
This was my reponse . . .
\(\displaystyle \text{Rubbish?}\)
\(\displaystyle Think\text{ before you dispay your attitude . . .}\)
\(\displaystyle \text{If you wanted: }\:x^2 + 3x - \frac{2}{x^2} - 4,\,\text{ how would you write it?}\)
\(\displaystyle \text{Probably: }\:x^2 + 3x - 2/x^2 - 4\;\hdots\text{ right?}\)
. . \(\displaystyle \text{(The numerator and denominator are }clearly\text{ separated by the "/".)}\)
\(\displaystyle \text{According to your system, }all\text{ of these would be written the same way:}\)
. . \(\displaystyle \begin{array}{ccc} x^2 + 3x - \dfrac{2}{x^2-4} & \Rightarrow & x^2 + 3x - 2/x^2-4 \\ \\ x^2 + \dfrac{3x-2}{x^2} - 4 & \Rightarrow & x^2 + 3x - 2/x^2-4 \\ \\ x^2 + \dfrac{3x-2}{x^2-4} & \Rightarrow & x^2 + 3x - 2/x^2-4 \\ \\ \dfrac{x^2+3x-2}{x^2} - 4 & \Rightarrow & x^2 + 3x - 2/x^2-4 \\ \\ \dfrac{x^2 + 3x - 2}{x^2-4} & \Rightarrow & x^2 + 3x - 2/x^2 - 4 \end{array}\)
\(\displaystyle \text{So, what do you plan to do about it?}\)