\(\displaystyle x(x^2 + 5x - 6) = 0\)
\(\displaystyle x(x - 1)(x + 6) = 0\)
Setting each linear factor to 0 and solving for x:
\(\displaystyle (x - 1) = 0, x = 1\)
\(\displaystyle (x + 6) = 0, x = -6 \)
\(\displaystyle x = 0, x = 1, x = -6\)
I see that the 1 and -6 came from the linear factors of
\(\displaystyle (x - 1)\) and \(\displaystyle (x+6)\)
But where did the "0 root" come from?
\(\displaystyle x(x - 1)(x + 6) = 0\)
Setting each linear factor to 0 and solving for x:
\(\displaystyle (x - 1) = 0, x = 1\)
\(\displaystyle (x + 6) = 0, x = -6 \)
\(\displaystyle x = 0, x = 1, x = -6\)
I see that the 1 and -6 came from the linear factors of
\(\displaystyle (x - 1)\) and \(\displaystyle (x+6)\)
But where did the "0 root" come from?
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