Rolling Die???

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Word Problem Help I'm stuck: Question asked: Two dice are rolled, one at a time. Find the probability of rolling a 5 on the first die and a 2 on the second. Round to the nearest whole percent.
Answers given to choose from: 3%, 17%, 33% or 100%
I figured this out and got it wrong, but I figured 1/3rd and said 33%??
I know it's not 100% but am a little confused. Help
 
Word Problem Help I'm stuck: Question asked: Two dice are rolled, one at a time. Find the probability of rolling a 5 on the first die and a 2 on the second. Round to the nearest whole percent.
Answers given to choose from: 3%, 17%, 33% or 100%
I figured this out and got it wrong, but I figured 1/3rd and said 33%??
I know it's not 100% but am a little confused. Help

6 possible choices on the first die and 6 possible choices on the second die.

so 6+6=12 total choices.

Prob (5 and 2)= 2/12

1/6= 17%
 
I have a split headache, so I may very well be wrong, but this was my thinking:

The problem says we need a 5 on the first die, and then a two on the second die.


Odds of rolling a 5: 1/6

Odds of rolling a 2: 1/6

But wouldn't the odds of rolling a 5 and then a two be 1/6 x 1/6=1/36=3%?


Again, probability isn't really my "thing," and I'm not thinking too clearly right now, but can you tell me what's wrong with my logic? Thanks,


-Daniel-
 
I believe the clincher here is "rolled the dice one at a time". If the dice were rolled at the same time the probability would be 1/36.

Probability has never been my forte either.
 
It doesn't matter if the two dice are rolled separately or together.
It doesn't matter if you roll two dice or roll one die twice.
. . The events are independent . . . 1/6 each time for any particular number.

There are: 6 x 6 = 36 possible outcomes.

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

There is only <u>one</u> way to get a 5 on the first die and 2 on the second.

. . Pr(5, then 2) = 1/36
 
I was wondering about that Soroban. I knew the probability was 1/36 for rolling two dice but I thought maybe "rolled one at a time" made a difference.
 
Well, introducing a 2nd dice was just to add spice, right?
Same thing as 1 dice, 2 rolls: 5 then 2; 1/36 evidently.
 
well, its P(5 and 2) = P(5) x P(2) coz theyre independant,

so P = 1/6 x 1/6 = 1/36 = 2.7recurring%

the probabilities are 1/6 coz in each case there are 6 equally likely outcomes.

so the answer wud be 3%
 
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