Right Angle = -1?

Where did you get such nonsense?

If you scaled the figure up or down, the relationship would go away; that implies angles are irrelevant.

The numbers used are very special; if the circumference is 1 more than the diameter, then the latter must satisfy the equation \(\pi d = d + 1\), whose solution is \(d = \frac{1}{\pi-1} = 0.46694220692425985998339481323367\).

So the relationship has nothing to do with the figure (especially the inscribed right angle), but entirely with the particular number used.
 
Thank you for the quick answere!

I apologyse, I just wanted to know if this statement is true:

"The product of the gradient of two lines at right angles is '-1'."

I found that diagram on an long forgotten website. If it is nonsense, then no one will find it... unless they dig deep.

Many thanks!
 
Lalµnaleymoon said:
I just wanted to know if this statement is true:

"The product of the gradient of two lines at right angles is '-1'."
Click to expand...
That's an entirely different question. It's true, as long as neither line is vertical.

But it has nothing at all to do with the figure or claim you showed. A right angle is not "equivalent to -1".
 
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