Rewriting an equation

[caligirl350]

Rewrite as an equivalent exponential equation. Do not solve.

log10 1 = 0

I don't get???

 

[masters]

Rewrite as an equivalent exponential equation. Do not solve.

log10 1 = 0

I don't get???

Hi caligirl350,

Recall: If \(\displaystyle \log_{b}x=y\), then \(\displaystyle b^y=x\)

Does that help?

 

[caligirl350]

No, I still do not get. sorry.

 

[masters]

No, I still do not get. sorry.

Hello again caligirl350,

Ok, let's review.

\(\displaystyle \log_bx=y\) means \(\displaystyle x=b^y\)

Therefore, a logarithm is an exponent.

Here are a few examples:

(1) \(\displaystyle \log_3 9=2\) means \(\displaystyle 9=3^2\). Saavy?

(2) \(\displaystyle \log_{10}100=2\) means \(\displaystyle 100=10^2\)

Your problem asked about \(\displaystyle \log_{10}1=0\). This means \(\displaystyle 10^0=1\).

Go http://www.purplemath.com/modules/logs.htm for more information.

 

[caligirl350]

Oh, now I understand. Thank you very much!