REVIEW OF PREREQUISITE SKILLS

By factoring. Multiply it out to check. Remember FOIL?
 
this is what i got....
16n2 + 8n + 1
= (16n2 +4n) (2n +1)
= 4n(4n +1) (2n +1)

thats not right? :S
the answer is suppose to be (4n+1) 2
 
Note: In what follows, I will be assuming that your subscripted "2" is meant to be a superscripted exponent.

How did you get that 16n<sup>2</sup> + 8n + 1 equalled (16n<sup>2</sup> + 4n)(2n + 1)? You should be able to see, even without multiplying things out, that your factors will produce a cubic, which isn't what you started with:

. . . . .(16n<sup>2</sup> + 4n)(2n + 1)

. . . . .= (16n<sup>2</sup>)(2n) + (16n<sup>2</sup>)(1) + (4n)(2n) + (4n)(1)

. . . . .=32n<sup>3</sup> + 24n<sup>2</sup> + 4n

Please follow the instructions that were provided earlier: multiply out (4n + 1)<sup>2</sup>, and see what you get.

Eliz.
 
16n2 + 8n2 +1
= 16n2 + 4n + 4n+ 1
= (16n2 + 4n) (4n+1)
= 4(4n+1) (4n+1)
= 4(4n+1)2
 
example:
2w2 + 3w +1
= 2w2 +2w + 1w +1
= (2w2 + 2w) + ( 1w+1)
= 2w(w+1) + 1(w+1)
= (2w+1) (w+1)[/list]
 
How did "8n" (from the original equation) become "8n<sup>2</sup>"? How did "8n<sup>2</sup>" (first line) become "4n + 4n" (second line)? How did "16n<sup>2</sup> + 4n + 4n + 1" (second line) become "64n<sup>3</sup> + 32n<sup>2</sup> + 4n" (third line, multiplied out)?

Please review how to factor quadratics; many lessons are available online. And also please review how to multiply polynomials, so you can follow the instructions, provided earlier, on how to confirm that (4n + 1)<sup>2</sup> = 16n<sup>2</sup> + 8n + 1.

Eliz.
 
Get this stuck in your head:

(a+b)<sup>2</sup> = a<sup>2</sup> + 2*a*b + b<sup>2</sup>

Or the other way

a<sup>2</sup> + 2*a*b + b<sup>2</sup> = (a+b)<sup>2</sup>

Now your problem: 16n<sup>2</sup>+ 8n + 1

Look at each term in light of that thing I told you to get stuck in your head.

16n<sup>2</sup> = (4*n)<sup>2</sup>
1 = 1<sup>2</sup>

This leads to 16n<sup>2</sup>+ 8n + 1 = (4*n)<sup>2</sup>+ 8n + 1<sup>2</sup> = (4*n)<sup>2</sup>+ 2*(4*n)*1 + 1<sup>2</sup>
 
I'm sorry, but I don't understand how this relates to the question at hand...?

Eliz.
 
i got the answer ...
16n2 + 8n + 1 ax2+bx+c
product of 16
sum of 8
4 * 4 = 16
4 + 4 = 8

=(16n2+4n) (4n+1)
=4(4n+1) + 1(4n+1)
= (4n+1)

=)
thanks for ur help!
 
Please post new questions as new threads, not as replies to old questions, where they are frequently overlooked.

When you post this question, please include the instructions, and show whatever you have tried thus far. Thank you.

Eliz.
 
You must log in or register to reply here.
Top