Reuleaux triangle

jazziza87

New member
Joined
Apr 2, 2006
Messages
28
I have a problem in my math that tells me to create a Reuleaux triangle using the five vetices of a regular pentagon. Could someone explain me how to go about doing it. Thanks alot you guys for your help :D
 
jazziza87 said:
I have a problem in my math that tells me to create a Reuleaux triangle using the five vertices of a regular pentagon.
Surely the problem says Reuleaux polygon on a regular pentagon??
In that case, using the length of a diagonal of the pentagon as a radius draw arcs from each vertex of the opposite side.
 
Hey pka, that is what I thought when I looked it up but it tells me clearly to create a Reuleaux triangle using the vertices o a pentagon. Maybe they made a mistake, is it impossible to do that?
 
reulpoly6ga.gif

No, it is possible to have a Reuleaux polygon on a regular pentagon.
As you can see I have drawn two of its arcs.

It is impossible to have a Reuleaux triangle on a regular pentagon.
Reuleaux polygons are point sets in the plane with constant width.
 
jazziza87 said:
I have a problem in my math that tells me to create a Reuleaux triangle using the five vetices of a regular pentagon. Could someone explain me how to go about doing it. Thanks alot you guys for your help
The Reuleaux triangle is defined as follows.

1--Draw an equilateral triangle with sides equal to "r".
2--With a vertex as center, swing an arc of radius "r" between the other two vertices.
3--Repeat this at the other two vertices and you will have an equilateral triangle with three equal length, equal radius curved legs.
4--This shape has a constant width of "r".

Consequently, a manhole cover of this shape will never fall through the hole it is covering as the width of the hole is always smaller than the cover by the typical overlap.
 
Top