G
Guest
Guest
I forget how you're suppose to do restrictions for an equation like this:
(x^2-x-6)/ (x-3)
= (x-3)(x+2)/(x-3)
= x+2, restrictions : x can not equal 3
I get how you do (x-3)=0, therefore equals 3, but how come its not done to the (x+2) as well? do you only do it to the numbers you cancel out?
-Anna
(x^2-x-6)/ (x-3)
= (x-3)(x+2)/(x-3)
= x+2, restrictions : x can not equal 3
I get how you do (x-3)=0, therefore equals 3, but how come its not done to the (x+2) as well? do you only do it to the numbers you cancel out?
-Anna